With a gorgeous interface and drag & drop simplicity no need for complicated options.| | Insanely Fast| Permute was engineered to be incredibly fast. Permute is the easiest to use media converter with it’s easy to use, no configuration, drag and drop interface, it will meet the needs to convert all your media.| | Easy to Use| Built from the ground up, Permute is a perfect example of what a Mac app should be.O.S.Mac OS X 10.8.5 or later, 64-bit processor.Permute 2 – Permute is the easiest to use media converter with it’s easy to use, no configuration, drag and drop….The speed of computers allows you to use brute-force methods, such as that outlined in #12 above. Total = 180 + 180 + 120 + 40 + 30 = 550 (I checked this total using your Permutations Generator).īefore computers, that's the only way you could determine these sorts of numbers/probabilities. Number of ways of selecting remaining one letter = PERMUT(3,1) = 3 Number of different quadruplicates for each letter = COMBIN(5,4) = 5 Number of ways of selecting quadruplicate = 2 (i.e. Number of permutations with exactly one quadruplicate: Number of different arrangements for each possibility = 10 (=COMBIN(5,3) x COMBIN(2,2))Ħ. SSSII, SSSPP, IIISS or IIIPP (=COMBIN(2,1)x COMBIN(2,2)) Number of ways of selecting double, triple = 4, i.e. Number of permutations with one double, one triple: Number of ways of selecting remaining two letters = PERMUT(3,2) = 6ĥ. Number of different triplicates for each letter = COMBIN(5,3) = 10 Number of ways of selecting triplicate = 2 (i.e. Number of permutations with exactly one triplicate: No of ways of selecting the remaining letter: 2Ĥ. 10 ways of placing the first duplicate, and for each of these, 3 ways of placing the second duplicate. Number of different duplicates for each letter = COMBIN(5,2) x COMBIN(3,2) = 30, i.e. Number of ways of selecting two duplicates, (i.e. Number of permutations with exactly two duplicates: No of ways of selecting remaining three X = 3! = 6 = PERMUT(3,3)ģ. No of different duplicates for each letter e.g. Possible duplicate letters = I,S or P = 3 Number of permutations with exactly one duplicate: Number of permutations with no duplicates = NIL obviously, plusĢ. Instead, you have to start thinking about the possible sub-sets, and determine the numbers and/or probabilities for each.įor example, if we want the number of 5-letter permutations you can make from MISSISSIPPI, you can add:ġ. In summary, all I'm saying is that once you get beyond the really simple questions, such as how many permutations of 3 can I make from 5 different letters, there is no simple, single formula that you can use manually, or codify into Excel. you have to think like a computer! I don't guarantee that my numbers above are correct, but the process is. So this approach is time consuming, and tricky. the number of permutations with 2 x s, 1 x X will be the same as for 2 x i, 1 x X. There will be some symmetries given that there are 4 i's and 4 s's, e.g. You'll need to consider many other combinations of duplicates, including So we need to eliminate 3 x 47 = 141 from the count. For each of these 3, there are 4x3=12 ways of selecting the i's and 4 ways of selecting the s, i.e. There are 3 ways this can happen: iis, isi or sii. Hence we need to eliminate 23 from the count. You can use a formula approach, but as I said in #7 above, it gets tricky listing all the duplicate possibilities to be eliminated. You can then use Data/Remove Duplicates to generate a list of non-duplicates, and count these.Ģ. This will list all 11x10x9 = 990 permutations, including duplicates. Use an algorithm like the VBA provided previously. If you want to count the number of permutations if you select three letters, say, you can do it two ways:ġ. Unfortunately there's no single simple formula when you are selecting less than the full number of letters. And similar for any other duplicated letter. With 4 i's always in the rearranged word, there are 4! ways of arranging i1, i2, i3 and i4, hence you need to divide by 4! to eliminate the i duplicates. There are 11! ways of re-arranging, including duplicates. The 11 out of 11 case is relatively simple because it uses all the letters.
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